The expression of the function is f(n)= 2^(6 - n) for n greater than 1
How to evaluate the function?
The function is given as:
f(n)= 64 * (1/2)^n for n greater than 1
So, we have:
f(n)= 64 * (1/2)^n
Express 64 as 2^6
f(n)= 2^6 * (1/2)^n
Express 1/2 as 2^-1
f(n)= 2^6 * (2^-1)^n
Evaluate the product
f(n)= 2^6 * 2^-n
Apply the law of indices to evaluate the product
f(n)= 2^(6 - n)
Hence, the value of the function is f(n)= 2^(6 - n) for n greater than 1
Read more about functions at:
https://brainly.com/question/2328150
#SPJ1
