For the given question, we will use the formula from part (b) to answer part (d)
The given function is as follows:
[tex]S=260.4914\cdot A^{0.2051}[/tex]
We will find the number of species (S) When A = 813
so, substitute with A = 813, then find S
[tex]S=260.4914\cdot813^{0.2051}\approx1029.563[/tex]
Rounding the answer to the nearest 10 species
So, the answer will be:
[tex]S=1030[/tex]
