RoselinaM644552 RoselinaM644552

25-10-2022
Mathematics

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In TUV, the measure of V=90°, the measure of U=58°, and TU = 38 feet. Find the length of VT to the nearest tenth of a foot.

In TUV the measure of V90 the measure of U58 and TU 38 feet Find the length of VT to the nearest tenth of a foot class=

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AddilynN14313 AddilynN14313

25-10-2022

Answer:

32.2 feet

Explanation:

The diagram given is a right angled triangle

Using the SOH CAH TOA identity

Given the following

Hypotenuse = 38

Opposite = x

Sin theta = opposite/hypotenuse

Sin 58 = x/38

x = 38sin58

x = 38(0.8480)

x = 32.23

Hence the length of VT to the nearest tenth of a foot. is 32.2feet

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