SecilyF667919 SecilyF667919
  • 25-10-2022
  • Mathematics
contestada

There are 6 woman running in a race. How many first second and third place possibilities can occur?

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AngeliseK66102 AngeliseK66102
  • 25-10-2022

Permutation formula:

[tex]P(n,r)=\frac{n!}{(n-r)!}[/tex]

In this case:

n is the nuber of woman in the race

r is the number of woman chosen (3 as you need to know the number of possibles 3 first places combinations)

[tex]\begin{gathered} P(6,3)=\frac{6!}{(6-3)!} \\ \\ =\frac{6!}{3!} \\ \\ =\frac{1\cdot2\cdot3\cdot4\cdot5\cdot6}{1\cdot2\cdot3} \\ \\ =4\cdot5\cdot6 \\ \\ =120 \end{gathered}[/tex]

Then, there are 120 first second and third place possibilities that can occur

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