FaelanN262015 FaelanN262015
  • 25-10-2022
  • Physics
contestada

If velocity of the car is given as v(t)= 10+3t+512. Determine the acceleration at t=2s.

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MiangelM542892 MiangelM542892
  • 25-10-2022

Given data

*The given velocity of the car is v(t)= 10 + 3t + 512

The acceleration of the car is calculated as

[tex]\begin{gathered} a(t)=\frac{d}{dt}(v(t)) \\ =\frac{d}{dt}(10+3t+512) \\ =3m/s^2 \end{gathered}[/tex]

Thus, the acceleration of the car at t = 2 s is 3 m/s^2

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