Respuesta :

[tex]\begin{gathered} \text{ Since it is a Rhombus:} \\ DC=BC \\ \text{Therefore:} \\ m\angle CBD=m\angle DBC \\ \text{For the }\Delta\text{CDB:} \\ 100+m\angle CBD+m\angle DBC=180 \\ 100+m\angle DBC+m\angle DBC=180 \\ 100+2m\angle DBC=180 \\ m\angle DBC=\frac{180-100}{2} \\ m\angle DBC=40 \end{gathered}[/tex]

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