Let l and w be the length and width of the rectangle, respectively.
Therefore, according to the question,
[tex]\begin{gathered} l=7w \\ and \\ P=32 \\ P=2l+2w \end{gathered}[/tex]
Therefore, solving for l and w,
[tex]\begin{gathered} l=7w \\ 2(l+w)=32 \\ \Rightarrow l=7w,l+w=16 \\ \Rightarrow7w+w=16 \\ \Rightarrow w=2 \\ and \\ \Rightarrow l=7*2=14 \end{gathered}[/tex]
The answer is length=14ft, width=2ft
