The transver cut by the parallel lines are proportional
The value of x can be determined as,
[tex]\begin{gathered} \frac{AB}{BC}=\frac{DE}{EF} \\ \frac{3}{5}=\frac{5+x}{24-(5+x)} \\ 3(19-x)=5(5+x) \\ 57-3x=25+5x \\ 32=8x \\ x=4 \end{gathered}[/tex]
Thus, the required value of x is 4.
