Respuesta :

nightmist
Mr of C6H12O6= (12*6)+(12*1)+(16*6)=180 
Mr of O2=(16*2)=32 

If 180 g of glucose requires 6*32 g of oxygen 
38 g of glucose would need 6*32/180 * 38=40.53 g of oxygen 
ans=40.53 

mr of CO2=44 
If 180 g of glucose gives 44*6 g of CO2 
therefore 38 g of it gives 44*6/180 * 38 = 55.73 g of CO2
yassirmomand
i think that it equal to co=3 h=2 o=1