athenavelazquez athenavelazquez
  • 25-04-2017
  • Mathematics
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sin(sin^-1[tex] \pi [/tex])

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Аноним Аноним
  • 25-04-2017
              When you want to find sin^-1 (pi/3) what you're asking is to find some x such that sin x = pi/3. Now note that pi/3 = 1.0472. So you want to find x such that sin x = 1.0472. But -1 <= sin x <= 1, this is the range of the sine function. So there is no value of x for which sin x = 1.0472.
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