If decomposition of 1 mole of ethylene with a gas density of 0.215g/mL starts at 29 degree celcius and the temperature increases by 950K, what is the final pressure of the confined gas?
We calculate first the initial pressure of the gas. P = nRT/V = (0.215 g/mL)(1 mol/16 g)(0.0821 L.atm/mol K)(302K) = 0.333 atm Using the relationship between the pressure and temperature, P1/T1 = P2/T2 Substituting the known values, (0.333 atm) / (29 + 273) = P2/(950) P2 = 1.05 atm
