that is the vertex since the leading coefient (the term in front of the the x^2 term)
get into form y=a(x-h)^2+k te vertex is (h,k) max value is k which occurs at x=h
complete the square h(t)=(2x^2+4x)+7 h(t)=2(x^2+2x)+7 h(t)=2(x^2+2x+1-1)+7 h(t)=2((x+1)^2-1)+7 h(t)=2(x+1)^2-2+7 h(t)=2(x+1)^2+5 vertex is at (-1,5) the max value is 5
