You need to break up the large square root into smaller square roots [tex] \sqrt{64x^{10}y^{19}z^{12}} [/tex] [tex] \sqrt{64} * \sqrt{x^{10}}* \sqrt{y^{19}} * \sqrt{z^{12}} [/tex]
Then we need to simplify the individual radicals [tex]8*x^{5}*y^{9} \sqrt{y} *z^{6}[/tex]
Now organize these together to get the radical at the end [tex]8x^{5}y^{9}z^{6} \sqrt{y} [/tex]
The answer is LETTER D. sqrt(64x^10y^19z^12) Break this down by number and variables. sqrt(64) = 8 sqrt(x^10) = x^5 because the index of 2 goes into the power of 10 5 times. sqrt(y^19) = sqrt(y^18*y) = y^9sqrt(y) because 2 goes into 18 9 times and leaves 1 y leftover. sqrt(z^12) = z^6 because 2 goes into 12 6 times
