The standard form of a circle is (x-h)²+(y-k)²=r², where h is the x-value of the center coordinate and k is the y-value.
Therefore, since the center is (10,-6), h=10 and k=-6. The radius is 6 which means r=6.
Substitute these values into the standard form equation.
(x-(10))²+(y-(-6))²=(6)²
(x-10)²+(y+6)²=36
Therefore, the standard equation for the circle centered at (10,-6) where r=6 is (x-10)²+(y+6)²=36.
