Respuesta :

[tex] \cfrac{7-4i}{2+i}\\\\ = \cfrac{(7-4i)(2-i)}{(2+i)(2-i)} \\\\ =\cfrac{14-7i-8i-4}{4+1} \\\\= \cfrac{10-15i}{5} \\\\= \cfrac{5(2-3i)}{5} \\\\=2-3i[/tex]