30 points if you answer this question and please show work !

The domain for f(x) and g(x) is the set of all real numbers.
Let f(x) = x2 +x-20 and g(x) = x +5
Find f(x)/g(x)

[tex]h(x)=\dfrac{f(x)}{g(x)}=\dfrac{x^2+x-20}{x+5}=\dfrac{x^2+x+4x-4x-20}{x+5}=\\\\\\= \dfrac{x^2+5x-4x-20}{x+5}=\dfrac{x(x+5)-4(x+5)}{x+5}=\dfrac{(x+5)(x-4)}{x+5}=\\\\\\=\boxed{x-4}[/tex]

We see, that g(x) is in denominator, so:

[tex]g(x)\neq0\\\\x+5\neq0\\\\\boxed{x\neq-5}[/tex]

and the domain of [tex]h(x)[/tex] is the set of all real numbers without [tex]x=-5[/tex].

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30 points if you answer this question and please show work ! The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = x2 +x-20 and g(x) = x +5 Find f(x)/g(x)

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30 points if you answer this question and please show work !

The domain for f(x) and g(x) is the set of all real numbers.
Let f(x) = x2 +x-20 and g(x) = x +5
Find f(x)/g(x)