jewellalbrightowzigl jewellalbrightowzigl
  • 24-10-2017
  • Mathematics
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find the discriminant and determine the number of real solutions : 4x^2 + 7x - 15 = 0

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eco92 eco92
  • 24-10-2017
The discriminant of a quadratic expression [tex]\displaystyle{ ax^2+bx+c[/tex] is 
                          [tex]\displaystyle{ D=b^2-4ac[/tex].

In the quadratic [tex]4x^2+7x-15[/tex], a=4, b=7, and c=-15.

Thus, [tex]\displaystyle{ D=b^2-4ac=7^2-4(4)(-15)=49+240=289>0[/tex].


The discriminant is positive, this means that the equation has 2 real solutions.

Answer: 2
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