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STRUCTURE OF BROMOUS ACID: H–O–Br=O

In this structure, all the elements have a formal charge of zero. The formal charge of each element is calculated below:

H: 1 – 1/2(2) – 0 = 0
O: 6 – 1/2(4) – 4 = 0
Br: 7 – 1/2(6) – 4 = 0
O: 6 – 1/2(4) – 4 = 0

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