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X and y are two positive numbers and y is three greater than x. the product of the numbers is 130. find the smaller number, x.

Respuesta :

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xy=130
y=3+x

x(3+x)=130
x²+3x-130=0
(x+13)(x-10)=0
x= -13 or 10

since the question says X and Y are positive we just dismiss-13

x=10
and y=13

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