thediamondgmr thediamondgmr
  • 22-01-2018
  • Mathematics
contestada


[tex] \frac{x - 5}{ - 2} = \frac{x - 1}{ - 3} [/tex]

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jdoe0001 jdoe0001
  • 22-01-2018
[tex]\bf \cfrac{x-5}{-2}=\cfrac{x-1}{-3}\implies \cfrac{5-x}{2}=\cfrac{1-x}{3}\impliedby \begin{array}{llll} \textit{let's multiply both sides}\\ \textit{by the LCD of 6, to do}\\ \textit{away with the denominators} \end{array} \\\\\\ 6\left( \cfrac{5-x}{2} \right)=6\left( \cfrac{1-x}{3} \right)\implies 3(5-x)=2(1-x) \\\\\\ 15-3x=2-2x\implies 13=x[/tex]
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