jennnnifer13842 jennnnifer13842
  • 26-01-2018
  • Mathematics
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5^2x=28
(Help me please!!!!!!)

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howaboutnope
howaboutnope howaboutnope
  • 26-01-2018
okay so i would do this with a logarithm. 
5^(2x) = 28 
take the log of both sides
log5^(2x) = log28   and because of this log rule: logA^n = nlogA 
(2x)log5= log28
then divide by log5 on both sides
2x = log28 / log5
and divide by 2
x = (log28 / log5) /2
this can be found with a calculator:

x= about 1.03521...
round that to whatever the question says to
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