Zombie0o
Zombie0o Zombie0o
  • 26-02-2018
  • Chemistry
contestada

NaCl + AgNO3 —> AgCl + NaNO3

How much AgNO3 is consumed during the reaction with 78 g of NaCl?

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Dejanras
Dejanras Dejanras
  • 07-03-2018
Answer is: 226,88 grams of AgNO₃ is consumed.
Chemical reaction: NaCl + AgNO
₃ → AgCl + NaNO₃.
m(NaCl) = 78 g.
n
(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 78 g ÷ 58,4 g/mol.
n(NaCl) = 1,335 mol.
From chemical reaction: n(NaCl) : n(AgNO₃) = 1 : 1.
n(AgNO₃) = 1,335 mol.
m(AgNO₃) = 1,335 mol · 169,87 g/mol.
m(AgNO₃) = 226,88 g.
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