naveed8966 naveed8966
  • 22-04-2018
  • Mathematics
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Find all real values of x such that ƒ(x) = 0 for ƒ(x) = 42 - 6x

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Аноним Аноним
  • 22-04-2018
0 = 42 - 6x
0 = -6(x - 7)
x = 7
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f(x) = x³ + 2x² - 13x + 10; 2
X-7=10 cuanto es X=-4