the balanced equation for the reaction between KOH and HF is KOH + HF ---> KF + H₂O stoichiometry of KOH to HF is 1:1 the number of HF moles reacted - 0.20 mol/L x 0.1000 L = 0.020 mol the number of KOH moles reacted - 0.10 mol/L x 0.2000 L = 0.020 mol KOH is a strong base and HF is a strong acid therefore they completely ionise into their corresponding ions KOH --> K⁺ + OH⁻ HF ---> H⁺ + F⁻ number of H⁺ moles reacted = number of OH⁻ moles reacted solution is completely neutralised no excess hydroxide or hydrogen ions therefore when solution is neutral , pH = 7 pH of solution = 7
