herediaj1226 herediaj1226
  • 26-06-2021
  • Mathematics
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Part II: Find the sine, cosine, and tangent ratios of <y ​

Part II Find the sine cosine and tangent ratios of lty class=

Respuesta :

adefunkeadewole adefunkeadewole
  • 01-07-2021

Answer:

sin θ = 22.62°

cos θ = 22.62°

tan θ = 22.62°

Step-by-step explanation:

From the diagram above

Opposite = 5

Adjacent = 12

Hypotenuse = 13

a) sin θ = Opp/Hypotenuse

sin θ = 5/13

sin θ = 0.3846153846

arc sin 0.3846153846

= 22.619864948°

Approximately = 22.62°

b) cos θ = Adjacent/ Hypotenuse

θ = 12/13

= arccos(0.9230769230769231)

22.619864948°

Approximately = 22.62°

c) tan θ = Opposite/Adjacent

θ = 5/12

= arctan(0.4166666666666667)

= 22.619864948°

= 22.62°

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